50 percent of a certain product have weight 60 kg or more whereas 10% have weight 55 kg or less. on the assumption of normality, what is the variance of weight? ​

variance = 3.9 kg

Step-by-step explanation:

Z score = (value - mean)/variance

50 percent of a certain product have weight 60 kg

for 50% z score = 0

value = 60 kg

=> 0 = (60 - mean)/variance

=> mean = 60

10% have weight 55 kg or less.

z score for 10% = -1.282

value = 55 kg

-1.282 = (55 - 60)/variance

=> variance = 5/1.282

=> variance = 3.9

variance = 3.9 kg

answer:

16.67.

Step-by-step explanation:

Percentage solution with steps:

Step 1: We make the assumption that 60 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that

Step 4: In the same vein,  

Step 5: This gives us a pair of simple equations:

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

Step 7: Taking the inverse (or reciprocal) of both sides yields

answer:

6 grams is the answer.

60 / 100  *  10

= 60 * 10 / 100

= 600 / 100

= 6

answer:

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